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In the given figure, O is center of the circle and ∠COD is greater than ∠AOB, then :

In the given figure, O is center of the circle and ∠COD is greater than ∠AOB, then : Circle, Concise Mathematics Solutions ICSE Class 9.
  1. AB > CD

  2. AB < CD

  3. AB = CD

  4. AB + CD = AD

Circles

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Answer

We know that,

Greater the chord, greater is the angle subtended by it at the center.

Given,

⇒ ∠AOB < ∠COD

⇒ AB < CD

Hence, Option 2 is the correct option.

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