In the given figure, we find :

1. AB > AC

2. AC > AB

3. AB < BC

4. AC = AB

From figure,

ABP is a straight line.

∴ ∠PBC + ∠ABC = 180°

⇒ 105° + ∠ABC = 180°

⇒ ∠ABC = 180° - 105° = 75°.

ACQ is a straight line.

∴ ∠ACB + ∠BCQ = 180°

⇒ 125° + ∠ACB = 180°

⇒ ∠ACB = 180° - 125° = 55°.

Since, ∠ABC > ∠ACB

∴ AC > AB (If two angles of a triangle are unequal, the greater angle has the greater side opposite to it.)

Hence, Option 2 is the correct option.