Mathematics
In the given triangle ABC, find a point P equidistant from AB and AC; and also equidistant from B and C.
Locus
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Answer
Steps of construction :
In the given triangle, draw the angle bisector of ∠BAC.
Draw the perpendicular bisector of BC which intersects the angle bisector at P.
Since, P lies on angle bisector of ∠BAC and also perpendicular bisector of BC.
Hence, P is the required point.
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