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Mathematics

In 57\dfrac{5}{7} xy2z3, write the coefficient of:

(i) 5

(ii) 57\dfrac{5}{7}

(iii) 5x

(iv) xy2

(v) z3

(vi) xz3

(vii) 5xy2

(viii) 17\dfrac{1}{7} yz

(ix) z

(x) yz2

(xi) 5xyz

Algebraic Expressions

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Answer

(i) Coefficient = 17\dfrac{1}{7} xy2z3

(ii) Coefficient = xy2z3

(iii) Coefficient = 17\dfrac{1}{7} y2z3

(iv) Coefficient = 57\dfrac{5}{7} z3

(v) Coefficient = 57\dfrac{5}{7} xy2

(vi) Coefficient = 57\dfrac{5}{7} y2

(vii) Coefficient = 17\dfrac{1}{7} z3

(viii) Coefficient = 5 xyz3

(ix) Coefficient = 57\dfrac{5}{7} xy2z2

(x) Coefficient = 57\dfrac{5}{7} xyz

(xi) Coefficient = 17\dfrac{1}{7} yz2

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