KnowledgeBoat Logo
|

Mathematics

Indicate whether the given statement is true or false :

(i) {Triangles} ⊆ {Quadrilaterals}

(ii) {Squares} ⊆ {Rectangles}

(iii) {Rhombuses} ⊆ {Parallelograms}

(iv) {Natural numbers} ⊆ {Whole numbers}

(v) {Integers} ⊆ {Whole numbers}

(vi) {Composite numbers} ⊆ {Odd numbers}

Sets

1 Like

Answer

(i) False
Reason — A triangle is a polygon with 3 sides, whereas a quadrilateral is a polygon with 4 sides. Since no triangle can be a quadrilateral, the set of triangles is not a subset of the set of quadrilaterals.

(ii) True
Reason — A square is defined as a special type of rectangle where all four sides are equal. Since every square satisfies the properties of a rectangle, the set of squares is a subset of the set of rectangles.

(iii) True
Reason — A rhombus is a quadrilateral with both pairs of opposite sides parallel and all sides equal. Since it satisfies the definition of a parallelogram (a quadrilateral with two pairs of parallel sides), the set of rhombuses is a subset of the set of parallelograms.

(iv) True
Reason — Natural numbers (N) are {1, 2, 3, …} and whole numbers (W) are {0, 1, 2, 3, ….}. Since every natural number is also a whole number, {Natural numbers} ⊆ {Whole numbers}.

(v) False
Reason — Integers include both, negative and positive numbers (…., -2, -1, 0, 1, 2, ….), whereas whole numbers consist only of zero and positive counting numbers. Since negative integers are not whole numbers, the set of integers is not a subset of whole numbers.

(vi) False
Reason — Composite numbers are numbers with more than two factors, such as 4, 6, 8, 9, 10, … . Many composite numbers (like 4, 6, and 8) are even, so the set of composite numbers is not a subset of the set of odd numbers.

Answered By

2 Likes


Related Questions