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Mathematics

cot2 θ1sin2 θ\text{cot}^2 \text{ θ} - \dfrac{1}{\text{sin}^2 \text{ θ}} is equal to

  1. 1

  2. -1

  3. sin2 θ

  4. sec2 θ

Trigonometric Identities

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Answer

Given,

cot2 θ1sin2 θ\text{cot}^2 \text{ θ} - \dfrac{1}{\text{sin}^2 \text{ θ}}

The equation can be written as,

cos2 θsin2 θ1sin2 θcos2 θ1sin2 θ(1cos2 θ)sin2 θsin2 θsin2 θ1.\Rightarrow \dfrac{\text{cos}^2 \text{ θ}}{\text{sin}^2 \text{ θ}} - \dfrac{1}{\text{sin}^2 \text{ θ}} \\[1em] \Rightarrow \dfrac{\text{cos}^2 \text{ θ} - 1}{\text{sin}^2 \text{ θ}} \\[1em] \Rightarrow \dfrac{-(1 - \text{cos}^2 \text{ θ})}{\text{sin}^2 \text{ θ}} \\[1em] \Rightarrow \dfrac{-\text{sin}^2 \text{ θ}}{\text{sin}^2 \text{ θ}} \\[1em] \Rightarrow -1.

Hence, Option 2 is the correct option.

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