|

Mathematics

$\dfrac{3x}{y^{-1}} + \dfrac{2y}{x^{-1}}$ is equal to :
6xy
3x² + 2y²
5xy
$\dfrac{6}{xy}$

Indices

15 Likes

Answer

Simplifying the expression :

$\Rightarrow \dfrac{3x}{y^{-1}} + \dfrac{2y}{x^{-1}} = \dfrac{3x}{\dfrac{1}{y}} + \dfrac{2y}{\dfrac{1}{x}} \\[1em] = 3xy + 2xy \\[1em] = 5xy.$

Hence, Option 3 is the correct option.

Answered By

11 Likes

Related Questions

$\dfrac{a^{-1}}{a^{-1} + b^{-1}}$ is equal to :
$\dfrac{b}{a + b}$
$\dfrac{a + b}{a}$
$\dfrac{a}{a + b}$
a(a + b)
View Answer

If $4^{2x} = \dfrac{1}{32}$ , the value of x is :
1.25
-1.25
1
-1
View Answer
$\Big(8^{-\dfrac{4}{3}} ÷ 2^{-2}\Big)$ is equal to :
$\dfrac{1}{4}$
$-\dfrac{1}{4}$
$-\dfrac{1}{2}$
$\dfrac{1}{2}$
View Answer
If 8^{2x + 5} = 1, value of x is :
$-\dfrac{5}{2}$
$\dfrac{5}{2}$
2
$\dfrac{2}{5}$
View Answer