Computer Applications
Kamal wants to display only the alphabets stored in a character array. While compiling the code, an error was displayed. Check for the statement with the error and write the correct statement.
char arr[]={'4', '&', 'a', 'w', 'd'};
int i;
for(i=0;i<arr.length;i++)
{
if(Character.isLetter(arr))
System.out.println(arr);
}
Answer
char arr[]={'4', '&', 'a', 'w', 'd'};
int i;
for(i=0;i<arr.length;i++)
{
if(Character.isLetter(arr)) //Error 1
System.out.println(arr); // Error 2
}
1. In Character.isLetter(arr), arr is the entire array, but the method expects a single character (char), not an array.
2. In System.out.println(arr), arr prints the whole array, not the individual character.
The corrected code is as follows:
char arr[] = {'4', '&', 'a', 'w', 'd'};
int i;
for(i = 0; i < arr.length; i++)
{
if(Character.isLetter(arr[i]))
System.out.println(arr[i]);
}
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