Mathematics
Keeping the place value of digit 3 in the number 730265 same, rearrange the digits of the given number to get the largest number and smallest number of 6 digits.
Answer
In the number 7,30,265, the digit 3 is at the ten thousand's place.
The place value of 3 = 3 × 10,000 = 30,000.
To keep the place value of 3 same, the digit 3 must remain at the ten thousand's place.
The remaining digits are 7, 0, 2, 6 and 5.
For the largest 6-digit number, arrange the remaining digits in descending order, with 3 fixed at the ten thousand's place:
Lakhs place: 7 (largest)
Ten thousands place: 3 (fixed)
Thousands place: 6
Hundreds place: 5
Tens place: 2
Ones place: 0
The largest 6-digit number = 7,36,520.
For the smallest 6-digit number, the digit at the lakh's place cannot be 0. So, place the smallest non-zero digit (excluding 3) at the lakh's place, which is 2. Then arrange the remaining digits in ascending order:
Lakhs place: 2
Ten thousands place: 3 (fixed)
Thousands place: 0
Hundreds place: 5
Tens place: 6
Ones place: 7
The smallest 6-digit number = 2,30,567.
Hence, the largest 6-digit number is 7,36,520 and the smallest 6-digit number is 2,30,567.
Related Questions
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