Mathematics
A ladder 17 m long reaches the window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.
Pythagoras Theorem
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Answer
Let AB be the ladder, BC be the building and B be the window.
Then, AB = 17 m, BC = 15 m
AC be the distance of the foot of the ladder from the building.
By Pythagoras theorem,
Hypotenuse2 = Perpendicular2 + Base2
In triangle ABC,
⇒ AB2 = BC2 + AC2
⇒ 172 = 152 + AC2
⇒ 289 = 225 + AC2
⇒ AC2 = 289 - 225
⇒ AC2 = 64
⇒ AC =
⇒ AC = 8 m.
Hence, the distance of the foot of the ladder from the building is 8 m.
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