The last term of the A.P., 5, 12, 19, ….. having 60 terms is :
406
412
416
418
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Given,
A.P. : 5, 12, 19, …….
a = 5
d = 12 - 5 = 7
n = 60
We know that,
nth term of A.P. :
∴ Tn = a + (n - 1)d
⇒ T60 = 5 + (60 - 1)7
= 5 + (59) × 7
= 5 + 413
= 418.
Hence, option 4 is the correct option.
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