What least number should be subtracted from 10,003 to get a number exactly divisible by 11?

1. 7

2. 6

3. 5

4. 4

Given number = 10,003.

To make 10003 exactly divisible by 11, we divide 10,003 by 11 and subtract the remainder from 10,003.

$\begin{array}{l} \phantom{x^2 +}{\quad 909} \ 11\overline{\smash{\big)}\quad 10003} \ \phantom{x^ + )}\phantom{)}\underline{-99} \ \phantom{{x^2 } + 2a} 10 \ \phantom{{x} +1a}\underline{-00} \ \phantom{{x^2 } + 2xa } 103 \ \phantom{{x} +1xa}\underline{-99} \ \phantom{{x^2 + 3x +)}} 4 \ \end{array}$

The remainder when 10003 is divided by 11 is 4.

Least number to be subtracted = remainder = 4.

Hence, option 4 is the correct option.