If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?
Polynomials
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Question

If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?

KnowledgeBoat · Accepted Answer

Let the width of the rectangle be x cm. Then, the length of the rectangle = (2x + 3) cm. Perimeter of a rectangle = 2(length + width) According to the question, the perimeter is 24 cm. So, 2[(2x + 3) + x] = 24 ⇒ 2[3x + 3] = 24 ⇒ 6x + 6 = 24 ⇒ 6x = 24 - 6 ⇒ 6x = 18 ⇒ x = ⇒ x = 3 So, Width of the rectangle = 3 cm Length of the rectangle = 2(3) + 3 = 6 + 3 = 9 cm Hence, the dimensions of the rectangle are: length = 9 cm and width = 3 cm.

Mathematics

If the length of a rectangle is three more than twice its width and its perimeter is 24 cm, what are the dimensions of the rectangle?

Polynomials

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