Mathematics
Let L be the lower class boundary of a class in a frequency distribution and m be the mid-point of the class. Which of the following is the upper boundary of the class?
m +
L +
2m - L
m - 2L
Statistics
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Answer
Let U be the upper boundary of the class.
As we know,
The mid-point is the average of the lower boundary and the upper boundary.
m =
⇒ 2m = L + U
⇒ U = 2m - L
Hence option 3 is the correct option.
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