Mathematics

Let p(x) = ax + b and q(x) = cx + d be two linear polynomials such that:
(i) p(0) = 5.
(ii) The polynomial p(x) – q(x) cuts the x-axis at (3, 0).
(iii) The sum p(x) + q(x) is equal to 6x + 4 for all real x.

Find the polynomials p(x) and q(x).

Polynomials

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Answer

Given:

p(x) = ax + b and q(x) = cx + d

Using condition (i): p(0) = 5

p(0) = a(0) + b

5 = b

⇒ b = 5

Using condition (iii): p(x) + q(x) = 6x + 4

p(x) + q(x) = (ax + b) + (cx + d)

= (a + c)x + (b + d)

Comparing with 6x + 4:

a + c = 6 …(i)

b + d = 4

Substituting b = 5:

5 + d = 4

⇒ d = -1

Using condition (ii): p(x) - q(x) cuts the x-axis at (3, 0)

p(x) - q(x) = (ax + b) - (cx + d)

= (a - c)x + (b - d)

Substituting b = 5 and d = -1:

p(x) - q(x) = (a - c)x + (5 - (-1)) = (a - c)x + 6

Since the graph cuts the x-axis at (3, 0), substituting x = 3, p(x) - q(x) = 0:

(a - c)(3) + 6 = 0

⇒ 3(a - c) = -6

⇒ a - c = -2 …(ii)

Solving (i) and (ii):

a + c = 6

a - c = -2

Adding:

2a = 4

⇒ a = 2

Substituting value of a in a + c = 6:

2 + c = 6

⇒ c = 4

So, a = 2, b = 5, c = 4, d = -1.

Hence, p(x) = 2x + 5 and q(x) = 4x - 1.

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