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The line segment joining A(-3, 1) and B(7, -5) is a diameter of a circle whose centre is C. Find the co-ordinates of the centre C.

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Answer

Since the line segment joining points A and B is the diameter of the circle, the centre of the circle must be the mid-point of the diameter AB.

The line segment joining A(-3, 1) and B(7, -5) is a diameter of a circle whose centre is C. Find the co-ordinates of the centre C. Reflection, RSA Mathematics Solutions ICSE Class 10.

By using mid-point formula,

(x, y) = (x1+x22,y1+y22)\Big(\dfrac{x1 + x2}{2}, \dfrac{y1 + y2}{2}\Big)

Substituting values we get :

C(x,y)=(3+72,1+(5)2)C(x,y)=(42,42)C(x,y)=(2,2).\Rightarrow C(x, y) = \Big(\dfrac{-3 + 7}{2}, \dfrac{1 + (-5)}{2}\Big) \\[1em] \Rightarrow C(x, y) = \Big(\dfrac{4}{2}, \dfrac{-4}{2}\Big) \\[1em] \Rightarrow C(x, y) = (2, -2).

Hence, the coordinates of centre (C) are (2, -2).

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