Mathematics
(a) If the lines kx - y + 4 = 0 and 2y = 6x + 7 are perpendicular to each other, find the value of k.
(b) Find the equation of a line parallel to 2y = 6x + 7 and passing through (-1, 1)
Straight Line Eq
ICSE 2024
28 Likes
Answer
(a) 1st equation :
⇒ kx - y + 4 = 0
⇒ y = kx + 4
Slope (s1) : k
2nd equation :
⇒ 2y = 6x + 7
⇒ y =
⇒ y = 3x +
Slope (s2) : 3
We know that,
Product of slope of perpendicular lines = -1
⇒ k × 3 = -1
⇒ k =
Hence, k = .
(b) We know that,
Slope of parallel lines are equal.
Slope of line parallel to line 2y = 6x + 7 is 3.
By point-slope form :
⇒ y - y1 = m(x - x1)
⇒ y - 1 = 3[x - (-1)]
⇒ y - 1 = 3[x + 1]
⇒ y - 1 = 3x + 3
⇒ y = 3x + 3 + 1
⇒ y = 3x + 4.
Hence, equation of line parallel to 2y = 6x + 7 and passing through (–1, 1) is y = 3x + 4.
Answered By
7 Likes
Related Questions
Mr. Gupta invested ₹33000 in buying ₹100 shares of a company at 10% premium. The dividend declared by the company is 12%.
Find:
(a) the number of shares purchased by him.
(b) his annual dividend.
A life insurance agent found the following data for distribution of ages of 100 policy holders:
Age in years Policy holders (frequency) Cumulative frequency 20-25 2 2 25-30 4 6 30-35 12 18 35-40 20 38 40-45 28 66 45-50 22 88 50-55 8 96 55-60 4 100 On a graph sheet draw an ogive using the given data. Take 2 cm = 5 years along one axis and 2 cm = 10 policy holders along the other axis. Use your graph to find:
(a) The median age.
(b) Number of policy holders whose age is above 52 years.
Rohan bought the following eatables for his friends :
Soham Sweet Mart : Bill
S.No. Item Price Quantity Rate of GST 1 Laddu ₹ 500 per kg 2 kg 5% 2 Pastries ₹ 100 per piece 12 pieces 18% Calculate :
(a) Total GST paid.
(b) Total bill amount including GST.
Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm.
(a) Construct the locus of points equidistant from B and C.
(b) Construct the locus of points equidistant from A and B.
(c) Mark the point which satisfies both the conditions (a) and (b) as O. Construct the locus of points keeping a fixed distance OA from the fixed point O.
(d) Construct the locus of points which are equidistant from BA and BC.