A log of wood $6\dfrac{2}{7}$m in length, was cut into 11 pieces. What is the length of each piece?

Given :

Total length of a log of wood = $6\dfrac{2}{7}$ m = $\dfrac{44}{7}$ m

Number of pieces = 11

Length of each piece = ?

Length of each piece = (Total length of a log of wood) ÷ (Number of pieces)

Substituting the values in above, we get:

Length of each piece = $\dfrac{44}{7}$ m ÷ 11

$\begin{array}{ll} = \Big(\dfrac{44}{7} \times \dfrac{1}{11}\Big)\text{ m} & [\text{Reciprocal of } 11 \text{ is } \dfrac{1}{11}] \\ = \Big(\dfrac{4}{7} \times \dfrac{1}{1}\Big)\text{ m} & \text{[Simplifying 44 and 11 ⇒ Divide by 11]} \\ = \dfrac{4}{7}\text{ m} \\ \end{array}$

∴ The length of each piece = $\dfrac{4}{7}$ m