Mathematics
If the lower limit of a class-interval is 48 and the class-mark is 55, then the upper limit is :
60
62
64
61
Statistics
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Answer
Given,
Lowe limit = 48
Class mark = 55
Let upper limit be U.
As we know,
Class mark =
⇒ 55 × 2 = 48 + U
⇒ 110 = 48 + U
⇒ U = 110 - 48
⇒ U = 62
Hence option 2 is the correct option.
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Related Questions
If x and y are the lower limit and upper limit respectively of a class interval, then (y - x) gives the :
class mark
class size
range
frequency
In a grouped frequency distribution , the cumulative frequency of the last class interval denotes :
the frequency pertaining to that class
the maximum value of the variate
the total number of observations
none of these
If the class-intervals in a frequency distribution are 1 - 11, 11 - 21, 21 - 31, etc., then class 1 - 11 means :
more than 1 and less than 11
1 or more but less than 11
equal to or more than 1 but equal to or less than 11
more than 1 but less than or equal to 11
Directions:
Study the following table carefully and answer the questions that follow:
Age (in years) Number of employees (Frequency) Cumulative frequency 30 - 35 5 5 35 - 40 7 12 40 - 45 6 18 45 - 50 9 27 50 - 55 4 31 Based on above table, answer the following questions:
- The total number of employees is :
(a) 30
(b) 31
(c) 55
(d) Cannot be determined- How many employees are less than 50 years of age?
(a) 9
(b) 18
(c) 27
(d) 31- How many employees are atleast 40 years old?
(a) 12
(b) 18
(c) 19
(d) 27- What is the difference between the class-mark of the first and last class intervals?
(a) 20
(b) 22.5
(c) 25
(d) 27.5