Chemistry
M is a metal above hydrogen in the activity series and its oxide has the formula M2O. This oxide when dissolved in water forms the corresponding hydroxide which is a good conductor of electricity. In the above context answer the following :
(i) What kind of combination (bond) exists between M and O?
(ii) How many electrons are there in the outermost shell of M ?
(iii) State the reaction taking place at the cathode.
(iv) Which electrode: anode or cathode is the oxidising electrode? Why?
Acids Bases Salts
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Answer
(i) Electrovalent bond exits between M and O because the bond is formed between a metal and non-metal due to oppositely charged ions.
(ii) Number of electrons in the outer most shell of M is 1. It is so because the valency of O is -2 and as 2 atoms of M combine with O to form M2O, hence we can say that M has 1 valence electron.
(iii) At cathode : M+ (aq.) + e- ⟶ M (s)
(iv) Anode is the oxidizing electrode.
Reason — The anions donate the excess electrons to the anode and are oxidized to neutral atoms. Hence, the anode is the oxidizing electrode by which the electrons leave the electrolyte
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