A man saved ₹ 33,000 in 10 months. In each month after the first, he saves ₹ 100 more than he did in the preceding month. How much did he save in the first month?
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A man saved ₹ 33,000 in 10 months. In each month after the first, he saves ₹ 100 more than he did in the preceding month. How much did he save in the first month?

KnowledgeBoat · Accepted Answer

Let the man saved ₹ a in first month. The amount the man saved each month forms an Arithmetic Progression (A.P.) where : Total sum saved Sn = ₹ 33,000. Number of months (n) = 10 He saves ₹ 100 more than he did in the preceding month. Thus, d = 100 We know that, Sum of n terms of an A.P. is given by, ∴ Sn = [2a + (n - 1)d] ⇒ 33000 = [2a + (10 - 1)100] ⇒ 33000 = 5[2a + (9)100] ⇒ = [2a + 900] ⇒ 6600 = [2a + 900] ⇒ 6600 - 900 = 2a ⇒ 2a = 5700 ⇒ a = ⇒ a = ₹ 2,850. Hence, the amount man saved in first month is ₹ 2,850.

Mathematics

A man saved ₹ 33,000 in 10 months. In each month after the first, he saves ₹ 100 more than he did in the preceding month. How much did he save in the first month?

AP

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Mathematics

A man saved ₹ 33,000 in 10 months. In each month after the first, he saves ₹ 100 more than he did in the preceding month. How much did he save in the first month?

AP

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l + (n + 1)d
l − (n − 1)d
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