Manoj invested ₹ 8,000 for 10 years at 10% p.a. simple interest. The amount at the end of 2 years will be :

1. ₹ 9,600

2. ₹ 9,800

3. ₹ 16,000

4. None of these

Given:

P = ₹ 8,000

R = 10%

T = 2 years

$\because \text{S.I.} = ₹ \Big(\dfrac{P \times R \times T}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \Big(\dfrac{8,000 \times 10 \times 2}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \dfrac{1,60,000}{100}\\[1em] \Rightarrow \text{S.I.} = ₹ 1,600$

And,

$\text{A = P + S.I.}\\[1em] \Rightarrow\text{A} = ₹ 8,000 + ₹ 1,600\\[1em] \Rightarrow\text{A} = ₹ 9,600$

Hence, option 1 is the correct option.