How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to cover a rectangular region whose length and breadth are respectively:

(i) 70 cm and 36 cm

(ii) 144 cm and 1 m.

Area of one tile = length × breadth

= 12 × 5 sq. cm

= 60 sq. cm

(i) Length of the region = 70 cm

Breadth of the region = 36 cm

Area of the rectangular region = 70 × 36 sq. cm

= 2520 sq. cm

Number of tiles needed = $\dfrac{\text{Area of region}}{\text{Area of one tile}}$

= $\dfrac{2520}{60}$

= 42

Hence, 42 tiles are needed to cover the rectangular region.

(ii) Length of the region = 144 cm

Breadth of the region = 1 m = 100 cm

Area of the rectangular region = 144 × 100 sq. cm

= 14400 sq. cm

Number of tiles needed = $\dfrac{\text{Area of region}}{\text{Area of one tile}}$

= $\dfrac{14400}{60}$

= 240

Hence, 240 tiles are needed to cover the rectangular region.