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Mathematics

On a map drawn to a scale of 1 : 20000, a rectangular plot of land ABCD has AB = 32 cm and BC = 24 cm. Calculate :

(i) the diagonal distance of the plot in km,

(ii) the area of the plot in sq. km.

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Answer

On a map drawn to a scale of 1 : 20000, a rectangular plot of land ABCD has AB = 32 cm and BC = 24 cm. Calculate. Similarity, RSA Mathematics Solutions ICSE Class 10.

(i) By pythagoras theorem,

⇒ AC2 = AB2 + BC2

⇒ AC2 = 322 + 242

⇒ AC2 = 1024 + 576

⇒ AC2 = 1600

⇒ AC = 1600\sqrt{1600} = 40 cm.

Given,

Scale of map = 120000\dfrac{1}{20000}

Length of diagonal distance in map = k × Actual length of diagonal of plot

40 = 120000\dfrac{1}{20000} × Actual length of diagonal of plot

Actual length of diagonal of plot = 40 × 20000 = 800000 cm

= 800000100000\dfrac{800000}{100000} = 8 km.

Hence, diagonal distance of plot = 8 km.

(ii) Area of plot on map = AB × BC = 24 × 32 = 768 cm2

Area of plot on map = k2 × Area of actual plot

768 = (120000)2\Big(\dfrac{1}{20000}\Big)^2 × Area of actual plot

Area of actual plot = 768 × 20000 × 20000 cm2

= 768×20000×20000100000×100000\dfrac{768 \times 20000 \times 20000}{100000 \times 100000} km2

= 30.72 km2

Hence, area of plot = 30.72 km2.

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