KnowledgeBoat Logo
|

Mathematics

The marks obtained by 35 students in an examination are given below :

370, 290, 318, 175, 170, 410, 378, 405, 380, 375, 315, 305, 325, 275, 241, 288, 261, 355, 402, 380, 178, 253, 428, 240, 210, 175, 154, 405, 380, 370, 306, 460, 328, 440, 425

Form cumulative frequency table with class intervals of length 50.

Statistics

2 Likes

Answer

Minimum mark = 154

Maximum mark = 460

Given class length = 50

So we can take class intervals as

150 - 200, 200 - 250, 250 - 300, 300 - 350, 350 - 400, 400 - 450, 450 - 500,

Frequency distribution table :

MarksTally-MarksFrequencyCumulative frequency
150 - 200IIII55
200 - 250III38 (5 + 3)
250 - 300IIII513 (8 + 5)
300 - 350IIII I619 (13 + 6)
350 - 400IIII III827 (19 + 8)
400 - 450IIII II734 (27 + 7)
450 - 500I135 (34 + 1)
Total35

Answered By

1 Like


Related Questions