If the mean of the data y1, y2, y3, ...., yn is 102, then the mean of the data 5y1, 5y2, 5y3, ...., 5yn is : 1. 102 2. 204 3. 510 4. 606

Mean of y1, y2, y3, ...., yn is 102 So, New observation is : 5y1, 5y2, 5y3, ...., 5yn Since, ∴ = 510. Hence, option 3 is the correct option.

Mathematics

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Mean of y₁, y₂, y₃, …., y_n is 102

So,

$\dfrac{y$

New observation is :

5y₁, 5y₂, 5y₃, …., 5y_n

$\text{New Mean} = \dfrac{5y$

Since,

$\dfrac{y$

∴ $\text{New Mean} = 5 \times 102$ = 510.

Hence, option 3 is the correct option.

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