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Physics

The mechanical advantage of a machine is 2. It is used to raise a load of 15 kgf. What effort is needed?

Machines

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Answer

Given,

Mechanical advantage of the machine = 2

Load = 15 kgf

As,

Mechanical Advantage=LoadEffort⇒Effort=LoadMechanical Advantage=15 kgf2=7.5 kgf\text {Mechanical Advantage}=\dfrac{\text {Load}}{\text {Effort}} \\[1 em] \Rightarrow \text {Effort} = \dfrac{\text {Load}}{\text {Mechanical Advantage}}=\dfrac{15 \text{ kgf}}{2}=7.5 \text{ kgf}

To raise a load of 15 kgf, an effort of 7.5 kgf is needed.

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