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Mathematics

Mohan bought a certain number of notebooks for ₹ 600. He sold 14\dfrac{1}{4} of them at 5 percent loss. At what price should he sell the remaining notebooks so as to gain 10% on the whole ?

Profit, Loss & Discount

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Answer

Given:

C.P. of notebooks = ₹ 600

Gain desired on the whole = 10 %

Profit%=profitC.P×100\text{Profit\%} = \dfrac{\text{profit}}{\text{C.P}}\times 100

Putting the values, we get

10=Profit600×100Profit=10×600100=6000100=6010 = \dfrac{\text{Profit}}{600} \times 100\\[1em] \Rightarrow \text{Profit} = \dfrac{10 \times 600}{100}\\[1em] = \dfrac{6000}{100}\\[1em] = 60

As we know,

Profit=S.P. - C.P.\text{Profit} = \text{S.P. - C.P.}

Putting the values, we get

60=S.P.600S.P.=60+600=66060 = \text{S.P.} - 600\\[1em] \Rightarrow \text{S.P.} = 60 + 600\\[1em] = 660

C.P. of 14\dfrac{1}{4}number of notebooks = ₹ 14×600\dfrac{1}{4} \times 600

= ₹ 6004\dfrac{600}{4}

= ₹ 150150

Loss of 14\dfrac{1}{4}number of notebooks = 5%

Loss%=LossC.P×100\text{Loss\%} = \dfrac{\text{Loss}}{\text{C.P}}\times 100

Putting the values, we get

5=Loss150×100Loss=5×150100=750100=7.55 = \dfrac{\text{Loss}}{150} \times 100\\[1em] \Rightarrow \text{Loss} = \dfrac{5 \times 150}{100}\\[1em] = \dfrac{750}{100}\\[1em] = 7.5

As we know,

Loss=C.P. - S.P.\text{Loss} = \text{C.P. - S.P.}

Putting the values, we get

7.5=150S.P.S.P.=1507.5=142.57.5 = 150 - \text{S.P.}\\[1em] \Rightarrow \text{S.P.} = 150 - 7.5\\[1em] = 142.5

The S.P. of rest of notebooks = ₹ 660 - ₹ 142.5 = ₹ 517.5

The selling price of the rest of the notebooks = ₹ 517.50.

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