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Mathematics

Mohit draws a card from a well-shuffled deck of 52 cards. Find the probability of getting :

(i) a jack of red suit

(ii) 5 or 9 of club

(iii) a diamond card

(iv) 2 or 3 or 5 of black suit.

Probability

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Answer

(i) There are two jack of red suit (1 of diamond and 1 of heart).

∴ No. of favourable outcomes = 2

P(drawing a jack of red suit) = No. of favourable outcomesNo. of total possible outcomes=252=126\dfrac{\text{No. of favourable outcomes}}{\text{No. of total possible outcomes}} = \dfrac{2}{52} = \dfrac{1}{26}.

Hence, probability of getting a jack of red suit = 126\dfrac{1}{26}.

(ii) There is one each card of club numbered 5 and 9.

∴ No. of favourable outcomes = 2

P(drawing a 5 or 9 of club) = No. of favourable outcomesNo. of total possible outcomes=252=126\dfrac{\text{No. of favourable outcomes}}{\text{No. of total possible outcomes}} = \dfrac{2}{52} = \dfrac{1}{26}.

Hence, probability of drawing a 5 or 9 of club = 126\dfrac{1}{26}.

(iii) There are 13 diamond cards in a deck.

∴ No. of favourable outcomes = 13

P(drawing a diamond) = No. of favourable outcomesNo. of total possible outcomes=1352=14\dfrac{\text{No. of favourable outcomes}}{\text{No. of total possible outcomes}} = \dfrac{13}{52} = \dfrac{1}{4}.

Hence, probability of drawing a diamond = 14\dfrac{1}{4}.

(iv) There is one each card of club and spade numbered 2, 3 or 5.

∴ No. of favourable outcomes = 6

P(drawing a 2 or 3 or 5 of black suit.) = No. of favourable outcomesNo. of total possible outcomes=652=326\dfrac{\text{No. of favourable outcomes}}{\text{No. of total possible outcomes}} = \dfrac{6}{52} = \dfrac{3}{26}.

Hence, probability of drawing a 2, 3 or 5 of black suit. = 326\dfrac{3}{26}.

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