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Mathematics

Mr. Gautam sold a certain number of ₹ 20 shares paying 8% dividend at ₹ 18 and invested the proceed in ₹ 10 shares paying 12% dividend at 50% premium. If the change in his annual income is ₹ 120, find the number of shares sold by Mr. Gautam.

Shares & Dividends

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Answer

Let the number of shares Mr. Gautam sold be x.

For initial shares,

N.V. = ₹ 20

Rate of dividend = 8%

By formula,

Annual income (from first investment) = No. of shares × Rate of div. × N.V. of 1 share

= x × 8100\dfrac{8}{100} × 20

= 8x5\dfrac{8x}{5}

S.P. of each share = ₹ 18.

Amount obtained on selling shares = S.P × No. of shares = ₹ 18x.

The proceeds he invested in ₹ 10 shares at ₹ 15, paying 12% dividend.

N.V. = ₹ 10

Premium = 50% of ₹ 10 = 50100×10\dfrac{50}{100} \times 10 = 5

M.V. = N.V. + Premium = ₹ 10 + 5 = ₹ 15

Number of shares = Total investmentMarket value of each share\dfrac{\text{Total investment}}{\text{Market value of each share}}

=18x15=6x5= \dfrac{18x}{15} = \dfrac{6x}{5}

The change in Mr. Gautam's annual income = ₹ 120

By formula,

Annual income (from second investment) = No. of shares × Rate of div. × N.V. of 1 share

= 6x5×12100×10\dfrac{6x}{5} \times \dfrac{12}{100} \times 10

= 720x500=36x25\dfrac{720x}{500} = \dfrac{36x}{25}

Given, change in income = ₹ 120

8x536x25=12040x36x25=1204x25=120x=120×254x=750.\therefore \dfrac{8x}{5} - \dfrac{36x}{25} = 120 \\[1em] \Rightarrow \dfrac{40x - 36x}{25} = 120 \\[1em] \Rightarrow \dfrac{4x}{25} = 120 \\[1em] \Rightarrow x = \dfrac{120 \times 25}{4} \\[1em] \Rightarrow x = 750.

Hence, Mr. Gautam sold 750 shares.

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