Multiply :
23\dfrac{2}{3}32 ab by - 14\dfrac{1}{4}41 a2b
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23ab×(−14a2b)=−2×13×4a1+2b1+1=−212a3b2=−16a3b2\dfrac{2}{3}ab \times \Big(-\dfrac{1}{4}a^2b\Big)\\[1em] = -\dfrac{2 \times 1}{3 \times 4}a^{1+2}b^{1+1}\\[1em] = -\dfrac{2}{12}a^3b^2\\[1em] = -\dfrac{1}{6}a^3b^232ab×(−41a2b)=−3×42×1a1+2b1+1=−122a3b2=−61a3b2
Hence, 23\dfrac{2}{3}32 ab x (- 14\dfrac{1}{4}41 a2b) = −16-\dfrac{1}{6}−61a3b2.
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