Mathematics
What is the nature of the roots of the equation, 2x2 - 6x + 3 = 0?
rational and unequal
irrational and unequal
real and equal
imaginary and unequal
Quadratic Equations
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Answer
Comparing 2x2 - 6x + 3 = 0 with ax2 + bx + c = 0 we get,
a = 2, b = -6 and c = 3.
We know that,
⇒ D = b2 - 4ac
⇒ D = (-6)2 - 4(2)(3)
⇒ D = 36 - 24
⇒ D = 12
⇒ D > 0 roots are real and unequal.
⇒ D = 12 is not a perfect square, roots are irrational.
Thus, roots are irrational and unequal.
Hence, option 2 is the correct option.
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