Mathematics
The nature of roots of quadratic equation 3x2 − 6x − 3 = 0 are :
real and equal
real, distinct and rational
real, distinct and irrational
no real roots
Quadratic Equations
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Answer
Comparing 3x2 − 6x − 3 = 0 with ax2 + bx + c = 0, we get :
a = 3, b = -6, c = -3.
We know that,
⇒ D = b2 - 4ac
⇒ D = (-6)2 - 4 × (3) × (-3)
⇒ D = 36 + 36
⇒ D = 72.
∴ D > 0 and not a perfect square. Roots are real, distinct and irrational.
Hence, option 3 is the correct option.
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