If the nth term of an A.P. is given by (3n + 2), then the sum of its first three terms is :
21
24
27
32
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The nth term of the A.P. is given by,
Tn = 3n + 2
T1 = 3(1) + 2 = 5
T2 = 3(2) + 2 = 8
T3 = 3(3) + 2 = 11
Sum = 5 + 8 + 11 = 24.
Hence, option 2 is the correct option.
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How many numbers lying between 20 and 200 are divisible by 4?
43
44
45
46
The last term of the A.P., 5, 12, 19, ….. having 60 terms is :
406
412
416
418