In the nuclear decay given below : ZXA Z+1YA Z-1BA-4 Z-1BA-4 The particles emitted in the sequence are : 1. α, β, γ 2. β, α, γ 3. γ, β, α 4. β, γ, α

Question

KnowledgeBoat · Accepted Answer

β, α, γ Reason - In the first step, the atomic number increases from Z to Z + 1 while the mass number remains the same, which indicates β decay. - In the second step, the atomic number decreases from Z+1 to Z−1 and the mass number decreases by 4, which corresponds to α decay. - The final step shows no change in either atomic or mass number, indicating emission of γ radiation. Therefore, the sequence of emitted particles is β, α, γ.

Physics

In the nuclear decay given below :
_ZX^A ⟶ _Z+1Y^A ⟶ _Z-1B^A-4 ⟶ _Z-1B^A-4
The particles emitted in the sequence are :
α, β, γ
β, α, γ
γ, β, α
β, γ, α

Radioactivity

Answer

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