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Mathematics

On one day, a labourer earned ₹ 125. Out of this money, he spent ₹ 681268\dfrac{1}{2} on food, ₹ 203420\dfrac{3}{4} on tea and ₹ 162516\dfrac{2}{5} on other eatables. How much does he save on that day?

Fractions

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Answer

Given, expenses = ₹ 681268\dfrac{1}{2} on food, ₹ 203420\dfrac{3}{4} on tea and ₹ 162516\dfrac{2}{5} on other eatables

Total

6812+2034+16251372+834+825\Rightarrow 68\dfrac{1}{2} + 20\dfrac{3}{4} + 16\dfrac{2}{5}\\[1em] \Rightarrow \dfrac{137}{2} + \dfrac{83}{4} + \dfrac{82}{5}\\[1em]

LCM of 2, 4 and 5 = 20

137×102×10+83×54×5+82×45×4137020+41520+328201370+415+328202113201051320\Rightarrow \dfrac{137 \times 10}{2 \times 10} + \dfrac{83 \times 5}{4 \times 5} + \dfrac{82 \times 4}{5 \times 4}\\[1em] \Rightarrow \dfrac{1370}{20} + \dfrac{415}{20} + \dfrac{328}{20}\\[1em] \Rightarrow \dfrac{1370 + 415 + 328}{20} \\[1em] \Rightarrow \dfrac{2113}{20} \\[1em] \Rightarrow 105\dfrac{13}{20}

Savings = Income − Total expenses

Savings =125211320=125×2020211320=250020211320=2500211320=38720=19720\text{Savings }= 125 - \dfrac{2113}{20}\\[1em] = \dfrac{125 \times 20}{20} - \dfrac{2113}{20}\\[1em] = \dfrac{2500}{20} - \dfrac{2113}{20}\\[1em] = \dfrac{2500 - 2113}{20}\\[1em] = \dfrac{387}{20}\\[1em] = 19\dfrac{7}{20}

Hence, savings = 19720₹19\dfrac{7}{20}.

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