Paul is x years old and his father's age is twice the square of Paul's age. Ten years hence, father's age will be four times Paul's age. Find their present ages.
Quadratic Equations
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Question

Paul is x years old and his father's age is twice the square of Paul's age. Ten years hence, father's age will be four times Paul's age. Find their present ages.

KnowledgeBoat · Accepted Answer

Let paul's present age be x years Father's age = 2x² After 10 years, Paul's age = (x + 10) years Father's age = (2x² + 10) According to question, Since, age cannot be negative hence x ≠ -3 ∴ x = 5 , 2x² = 50 Paul's age is 5 years , while his father's age is 50 years.

Mathematics

Paul is x years old and his father's age is twice the square of Paul's age. Ten years hence, father's age will be four times Paul's age. Find their present ages.

Quadratic Equations

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