A point that lies on the line 2x - 3y = 4 can be taken as :

1. (-5, -2)

2. (-5, 2)

3. (5, 2)

4. (5, -2)

Given equation: 2x - 3y = 4

1. For (-5, -2):

Substitute x = -5 and y = -2

L.H.S. : 2 $\times$ (-5) - 3 $\times$ (-2)

= -10 + 6

= -4

R.H.S. = 4

Since, L.H.S. ≠ R.H.S., (-5, -2) does not lie on the line.

2. For (-5, 2):

Substitute x = -5 and y = 2

L.H.S. : 2 $\times$ (-5) - 3 $\times$ 2

= -10 - 6

= - 16

R.H.S. = 4

Since, L.H.S. ≠ R.H.S., (-5, 2) does not lie on the line.

3. For (5, 2):

Substitute x = 5 and y = 2

L.H.S. : 2 $\times$ 5 - 3 $\times$ 2

= 10 - 6

= 4

R.H.S. = 4

Since, L.H.S. = R.H.S., (5, 2) lies on the line.

4. For (5, -2):

Substitute x = 5 and y = -2

L.H.S. : 2 $\times$ 5 - 3 $\times$ (-2)

= 10 + 6

= 16

R.H.S. = 4

Since, L.H.S. ≠ R.H.S., (5, -2) does not lie on the line.

Hence, option 3 is the correct option.