Chemistry
Potassium (at No. 19) and chlorine (at No.17) react to form a compound. Explain on the basis of electronic concept :
(i) oxidation
(ii) reduction
(iii) oxidising agent
(iv) reducing agent.
Answer
The electronic configuration of:
Potassium (19) = 2, 8, 8, 1
Chlorine (17) = 2, 8, 7
The reaction is :
2K + Cl2 ⟶ 2K+ + 2Cl- or 2KCl
(i) Oxidation : 2K ⟶ 2K+ + 2e-
Potassium undergoes oxidation as it loses electron.
(ii) Reduction : Cl2 + 2e- ⟶ 2Cl-
Chlorine undergoes reduction as it gains electrons.
(iii) Chlorine acts as an oxidising agent and gets reduced.
(iv) Potassium acts as a reducing agent and gets oxidised.
Related Questions
Explain formation of electrovalent compound is a redox reaction.
Divide the following redox reactions into oxidation and reduction half reactions.
(i) Zn + Pb2+ ⟶ Zn2+ + Pb
(ii) Zn + Cu2+ ⟶ Zn2+ + Cu
(iii) Cl2 + 2Br- ⟶ Br2 + 2Cl-
(iv) Sn2+ + 2Hg2+ ⟶ Sn4+ + Hg22+
(v) 2Cu+ ⟶ Cu + Cu2+
What are the conditions necessary for the formation of covalent molecules ?
Elements A, B and C have atomic numbers 17, 19 and 10 respectively.
(a) State which one is : (i) a non-metal (ii) metal (iii) chemically inert ?
(b) Write down the formula of the compound formed by two of the above elements.