Consider the following code and then answer the questions that follow :

myDict = {'a' : 27, 'b' : 43, 'c' : 25, 'd' : 30}
valA =''
for i in myDict :
  if i > valA :
    valA = i
    valB = myDict[i]
print(valA)	            #Line1
print(valB)	            #Line2
print(30 in myDict)	    #Line3
myLst = list(myDict.items())
myLst.sort()	            #Line4
print(myLst[-1])	        #Line5

1. What output does Line 1 produce ?
2. What output does Line 2 produce ?
3. What output does Line 3 produce ?
4. What output does Line 5 produce ?
5. What is the return value from the list sort( ) function (Line 4) ?

What will be the output produced by following code ?

d1 = { 5 : "number", "a" : "string", (1, 2): "tuple" }   
print("Dictionary contents")
for x in d1.keys():	# Iterate on a key list
  print (x, ':' , d1[x], end = ' ')
  print (d1[x] * 3)
  print ( )

Predict the output:

d = dict()
d['left'] = '<'
d['right'] = '>'
d['end'] = ' '
print(d['left'] and d['right'] or d['right'] and d['left'])
print(d['left'] and d['right'] or d['right'] and d['left'] and d['end']) 
print((d['left'] and d['right'] or d['right'] and d['left']) and d['end']) 
print("end")

Predict the output:

text = "abracadabraaabbccrr" 
counts = {}
ct = 0
lst = []
for word in text:
  if word not in lst:
    lst.append(word)
    counts[word] = 0
  ct = ct + 1
  counts[word] = counts[word] + 1 
print(counts)
print(lst)