Predict the output :

L1= [x ** 2 for x in range(10) if x % 3 == 0]
L2 = L1
L1.append(len(L1))       
print(L1)
print(L2)      
L2.remove(len(L2) - 1) 
print(L1)

[0, 9, 36, 81, 4]
[0, 9, 36, 81, 4]
[0, 9, 36, 81]

Working

1. L1 = [x ** 2 for x in range(10) if x % 3 == 0] — This line creates a list L1 containing the squares of multiples of 3 between 0 to 9.
2. L2 = L1 — This line assigns list L1 to list L2, meaning both L1 and L2 reference the same list in memory (shallow copy).
3. L1.append(len(L1)) — This line appends the length of L1 to L1. So, the length of L1 is 4, and it appends 4 to L1.
4. print(L1) — This prints the modified L1 list.
5. print(L2) — This prints L2, which is pointing to the same list as L1.
6. L2.remove(len(L2) - 1) — This line removes the last element of L2 since len(L2) - 1 gives the last index of L2.
7. print(L1) — This prints L1 again. Since both L1 and L2 reference the same list, modifying L2 also affects L1. Therefore, L1 also reflects the change made to L2.