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Computer Science

Predict the output:

list1 = [2, 3, 3, 2, 5,3, 2, 5, 1,1] 
counts = {}
ct = 0
lst = []
for num in list1:
  if num not in lst:
    lst.append(num)
    counts[num] = 0
  ct = ct+1
  counts[num] = counts[num]+1 
print(counts)
for key in counts.keys():
  counts[key] = key * counts[key] 
print(counts)

Python Dictionaries

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Answer

Output
{2: 3, 3: 3, 5: 2, 1: 2} 
{2: 6, 3: 9, 5: 10, 1: 2} 
Explanation

This python program counts the frequency of each number in a list and then multiplies each frequency by its corresponding number. Here is a step-by-step explanation of the program:

  1. Initialize the variables
    1. The list1 variable stores the input list [2, 3, 3, 2, 5, 3, 2, 5, 1, 1].
    2. The counts variable is a dictionary that stores the frequency of each number in the list.
    3. The ct variable is a counter that keeps track of the total number of numbers in the list.
    4. The lst variable is a list that stores the unique numbers in the list.
  2. Loop through each number num in the list1
    1. If the number has not been seen before, it is added to the lst list and a new key is added to the counts dictionary with a value of 0.
    2. The ct variable is incremented by 1.
    3. The value of the number's key in the counts dictionary is incremented by 1.
  3. The counts dictionary is printed to the console after the first loop, displaying the frequency of each number in the list.
  4. Another loop is executed through the keys in the counts dictionary. For each key, its corresponding value is multiplied by the key and the new value is assigned back to the key in the counts dictionary.
  5. The final counts dictionary is printed to the console, showing the frequency of each number multiplied by the number itself.

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