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Mathematics

The probability of getting a number divisible by 3 in throwing a die is

  1. 16\dfrac{1}{6}

  2. 13\dfrac{1}{3}

  3. 12\dfrac{1}{2}

  4. 23\dfrac{2}{3}

Probability

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Answer

There are 2 numbers between 1 to 6 that are divisible by 3, i.e., 3 and 6.

∴ No. of favourable outcomes = 2

Total no. in a dice = 6.

∴ No. of possible outcomes = 6

P(a number divisible by 3) = No. of favourable outcomesNo. of possible outcomes=26=13\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{2}{6} = \dfrac{1}{3}.

Hence, option 2 is the correct option.

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