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Mathematics

The probability of getting a number divisible by 3 in throwing a die is:

  1. (16)\Big(\dfrac{1}{6}\Big)

  2. (13)\Big(\dfrac{1}{3}\Big)

  3. (12)\Big(\dfrac{1}{2}\Big)

  4. (23)\Big(\dfrac{2}{3}\Big)

Probability

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Answer

When a die is thrown, the possible outcomes are:

S = {1, 2, 3, 4, 5, 6}

Total number of outcomes = 6

Let E be the event of getting a number divisible by 3, then

E = {3, 6}

The number of favorable outcomes to the event E = 2

∴ P(E) = Number of favorable outcomesTotal number of outcomes=26=13\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{2}{6} = \dfrac{1}{3}

Hence, option 2 is the correct option.

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