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Mathematics

The probability that a leap year has 53 Sundays is:

  1. (17)\Big(\dfrac{1}{7}\Big)

  2. (27)\Big(\dfrac{2}{7}\Big)

  3. (37)\Big(\dfrac{3}{7}\Big)

  4. (47)\Big(\dfrac{4}{7}\Big)

Probability

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Answer

In a leap year, there are 366 days.

366 days = 52 weeks + 2 days

These 2 days can be (Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat), (Sat, Sun), and (Sun, Mon).

Total number of possible outcomes = 7

Number of favourable outcomes (Getting Sunday as one of the extra days) = 2 (i.e., (Sat, Sun), (Sun, Mon)).

Let E be the event that a leap year has 53 Sundays.

∴ P(E) = Number of favorable outcomesTotal number of outcomes=27\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{2}{7}

Hence, option 2 is the correct option.

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