What is the probability that a randomly chosen leap year has 52 Sundays? 1. 2. 3. 4.

Question

KnowledgeBoat · Accepted Answer

In a leap year, there are 366 days. 366 days = 52 weeks + 2 days The 7 possible pairs for the 2 extra days are:(Monday, Tuesday)(Tuesday, Wednesday)(Wednesday, Thursday)(Thursday, Friday)(Friday, Saturday)(Saturday, Sunday)(Sunday, Monday) Total number of possible outcomes = 7 Number of outcomes where a Sunday occurs = 2 [(Saturday, Sunday) and (Sunday, Monday)] Number of outcomes where a Sunday does not occur = 7 - 2 = 5. {i.e,(Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat)} Let E be the event that a leap year has exactly 52 Sundays, ∴ P(E) = Hence, option 3 is the correct option.

Mathematics

What is the probability that a randomly chosen leap year has 52 Sundays? 1. 2. 3. 4.

Probability

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