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Mathematics

Prove that :

3 cosec2 60° - 2 cot2 30° + sec2 45° = 0.

Trigonometric Identities

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Answer

3 cosec2 60° - 2 cot2 30° + sec2 45° = 0.

L.H.S. = 3 cosec2 60° - 2 cot2 30° + sec2 45°

=3×(23)22×(3)2+(2)2=3×(43)2×3+2=46+2=0= 3 \times \Big(\dfrac{2}{\sqrt3}\Big)^2 - 2 \times ({\sqrt3})^2 + ({\sqrt2})^2\\[1em] = 3 \times \Big(\dfrac{4}{3}\Big) - 2 \times 3 + 2\\[1em] = 4 - 6 + 2\\[1em] = 0

R.H.S. = 0

∴ L.H.S. = R.H.S.

Hence, 3 cosec2 60° - 2 cot2 30° + sec2 45° = 0.

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