Prove that the lines 2x + 3y + 8 = 0 and 27x – 18y + 10 = 0 are perpendicular to each other.
Straight Line Eq
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Question

Prove that the lines 2x + 3y + 8 = 0 and 27x – 18y + 10 = 0 are perpendicular to each other.

KnowledgeBoat · Accepted Answer

Converting 2x + 3y + 8 = 0 in the form y = mx + c we get, ⇒ 3y = -2x - 8 ⇒ y = Comparing, we get slope of this line : m1 = Converting 27x – 18y + 10 = 0 in the form y = mx + c we get, ⇒ -18y = -27x - 10 ⇒ y = ⇒ y = Comparing, we get slope of this line : m2 = Product of Gradients m1 × m2 = = = -1 Since the product of the gradients is -1. The lines are perpendicular to each other. Hence, proved that lines 2x + 3y + 8 = 0 and 27x – 18y + 10 = 0 are perpendicular to each other.

Mathematics

Prove that the lines 2x + 3y + 8 = 0 and 27x – 18y + 10 = 0 are perpendicular to each other.

Straight Line Eq

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