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Mathematics

Prove that :

sin 60° = 2 sin 30° cos 30°.

Trigonometric Identities

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Answer

sin 60° = 2 sin 30° cos 30°.

L.H.S. = sin 60° = 32\dfrac{\sqrt3}{2}

R.H.S.= 2 sin 30° cos 30°

=2×12×32=2×12×32=32= 2 \times \dfrac{1}{2} \times \dfrac{\sqrt3}{2}\\[1em] = \cancel{2} \times \dfrac{1}{\cancel{2}} \times \dfrac{\sqrt3}{2}\\[1em] = \dfrac{\sqrt3}{2}

∴ L.H.S. = R.H.S.

Hence proved, sin 60° = 2 sin 30° cos 30°.

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