Prove the following : cosθ/sin(90° - θ) + sinθ/cos(90° - θ) = 2

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KnowledgeBoat · Accepted Answer

To prove, We know that, sin (90 - θ) = cos θ and cos (90 - θ) = sin θ Solving L.H.S. of the equation, we get : Since, L.H.S. = R.H.S. Hence, proved that .

Mathematics

Prove the following : cosθ/sin(90° - θ) + sinθ/cos(90° - θ) = 2

Trigonometrical Ratios

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Without using trigonometric tables, evaluate :
sin² 34° + sin² 56° + 2 tan 18° tan 72° - cot² 30°.

Prove the following :
cos θ sin (90° - θ) + sin θ cos (90° - θ) = 1

Mathematics

Prove the following : cosθ/sin(90° - θ) + sinθ/cos(90° - θ) = 2

Trigonometrical Ratios

Related Questions

Without using trigonometric tables, evaluate :sin2 34° + sin2 56° + 2 tan 18° tan 72° - cot2 30°.

Prove the following :cos θ sin (90° - θ) + sin θ cos (90° - θ) = 1

Without using trigonometric tables, evaluate :
sin² 34° + sin² 56° + 2 tan 18° tan 72° - cot² 30°.

Prove the following :
cos θ sin (90° - θ) + sin θ cos (90° - θ) = 1